2. Boost Unordered Translation (zh_Hans)
3. Doc / Modules / Root / Pages / Reference / Unordered Set (adoc)
4. Chinese (Simplified Han script)
5. Zen

243 :977
	English Insert with Hint and `node_handle`
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — 带提示和 `node++_++handle` 的插入 26/340 · 34 Needs editing
244 :978
	English ```c++ iterator insert(const_iterator hint, node_type&& nh); ```
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — ```c++ iterator insert(const_iterator hint, node_type&& nh); ``` 72/640 · 64 Needs editing
:982 :982
	English If `nh` is empty, has no effect.
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — 若 `nh` 为空节点，则此操作不产生任何效果。 24/320 · 32 Needs editing
:984 :984
	English Otherwise inserts the element owned by `nh` if and only if there is no element in the container with an equivalent key.
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — 否则，当且仅当容器中不存在等价键的元素时，才会插入 `nh` 所拥有的元素。 38/1190 · 119 Needs editing
247 :986
	English If there is already an element in the container with an equivalent key has no effect on `nh` (i.e. `nh` still contains the node.)
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — 如果容器中已存在具有等价键的元素，则对 `nh` 不产生任何影响.（即 `nh` 仍持有该节点.） 49/1290 · 129 Needs editing
:988 :988
	English `hint` is a suggestion to where the element should be inserted.
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — `hint` 是插入元素位置的建议。 18/630 · 63 Needs editing
249 :991
	English Requires:;; `nh` is empty or `nh.get_allocator()` is equal to the container's allocator. Returns:;; If `nh` was empty returns `end()`. + + If there was already an element in the container with an equivalent key returns an iterator pointing to that. + + Otherwise returns an iterator pointing to the newly inserted element. Throws:;; If an exception is thrown by an operation other than a call to `hasher` the function has no effect. Notes:;; The standard is fairly vague on the meaning of the hint. But the only practical way to use it, and the only way that Boost.Unordered supports is to point to an existing element with the same key. + + Can invalidate iterators, but only if the insert causes the load factor to be greater to or equal to the maximum load factor. + + Pointers and references to elements are never invalidated. + + This can be used to insert a node extracted from a compatible `unordered_multiset`.
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — 要求：`nh` 为空或 `nh.get_allocator()` 与容器的分配器相等。返回：若 `nh` 为空，则返回 `end()`。+ +若容器中已存在等价的键，则返回指向该元素的迭代器。+ +否则，返回指向新插入元素的迭代器。抛出：若调用 `hasher` 以外的操作抛出异常，则函数无效果。说明：标准对 hint 的含义表述相当模糊。但使用它的唯一实际方式，也是 Boost.Unordered 唯一支持的方式，是将其指向具有相同键的现有元素。+ +可能使迭代器失效，但仅当插入导致负载因子大于或等于最大负载因子时才会发生。+ +指向元素的指针和引用永远不会失效。+ +该函数可用于插入从兼容的 `unordered_multiset` 中提取的节点。 330/9180 · 918 Needs editing
:1006 :1006
	English ---
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — --- 3/100 · 3 Needs editing
251 :1008
	English Erase by Position
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — 通过位置擦除 6/170 · 17 Needs editing
252 :1010
	English ```c++ iterator erase(iterator position); iterator erase(const_iterator position); ```
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — ```c++ iterator erase(iterator position); iterator erase(const_iterator position); ``` 86/860 · 86 Needs editing
:1015 :1015
	English Erase the element pointed to by `position`.
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — 擦除由 `position` 指向的元素。 21/430 · 43 Needs editing
254 :1018
	English Returns:;; The iterator following `position` before the erasure. Throws:;; Only throws an exception if it is thrown by `hasher` or `key_equal`. Notes:;; In older versions this could be inefficient because it had to search through several buckets to find the position of the returned iterator. The data structure has been changed so that this is no longer the case, and the alternative erase methods have been deprecated.
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — 返回：擦除前指向 `position` 之后位置的迭代器。抛出：仅当 `hasher` 或 `key_equal` 抛出异常时才会抛出异常。说明：在旧版本中，该操作可能效率较低，因为它需要搜索多个桶才能找到所返回迭代器的位置。数据结构已做修改，此问题已不复存在，并且其他替代的 `erase` 方法已被弃用。 154/4200 · 420 Needs editing
:1022 :1022
	English ---
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — --- 3/100 · 3 Needs editing
256 :1024
	English Erase by Value
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — 通过值擦除 5/140 · 14 Needs editing
257 :1025
	English ```c++ size_type erase(const key_type& k); template<class K> size_type erase(K&& k); ```
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — ```c++ size_type erase(const key_type&amp; k); template<class k=""> size_type erase(K&amp;&amp; k); ```</class> 111/880 · 88 Needs editing
258 :1030
	English Erase all elements with key equivalent to `k`.
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — 擦除所有键等价于 `k` 的元素。 17/460 · 46 Needs editing
259 :1033
	English Returns:;; The number of elements erased. Throws:;; Only throws an exception if it is thrown by `hasher` or `key_equal`. Notes:;; The `template<class K>` overload only participates in overload resolution if `Hash::is_transparent` and `Pred::is_transparent` are valid member typedefs and neither `iterator` nor `const_iterator` are implicitly convertible from `K`. The library assumes that `Hash` is callable with both `K` and `Key` and that `Pred` is transparent. This enables heterogeneous lookup which avoids the cost of instantiating an instance of the `Key` type.
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — 返回：擦除的元素数量。抛出：仅当 `hasher` 或 `key_equal` 抛出异常时才会抛出异常。说明：`template<class k="">` 重载仅在以下条件下参与重载决议：`Hash::is_transparent` 和 `Pred::is_transparent` 是有效的成员 typedef，且 `iterator` 和 `const_iterator` 均不能从 `K` 隐式转换。库假定 `Hash` 可同时以 `K` 和 `Key` 调用，且 `Pred` 是透明的。这实现了异构查找，从而避免了实例化 `Key` 类型对象的开销。</class> 288/5670 · 567 Needs editing
:1037 :1037
	English ---
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — --- 3/100 · 3 Needs editing
261 :1039
	English Erase Range
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — 范围擦除 4/110 · 11 Needs editing
262 :1041
	English ```c++ iterator erase(const_iterator first, const_iterator last); ```
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — ```c++ iterator erase(const_iterator first, const_iterator last); ``` 69/690 · 69 Needs editing