2. Boost Unordered Translation (zh_Hans)
3. Doc / Modules / Root / Pages / Reference / Unordered Map (adoc)
4. Chinese (Simplified Han script)
5. Zen

380 :1471
	English Effects:;; If the container does not already contain an elements with a key equivalent to `k`, inserts the value `std::pair<key_type const, mapped_type>(k, mapped_type())`. Returns:;; A reference to `x.second` where `x` is the element already in the container, or the newly inserted element with a key equivalent to `k`. Throws:;; If an exception is thrown by an operation other than a call to `hasher` the function has no effect. Notes:;; Can invalidate iterators, but only if the insert causes the load factor to be greater to or equal to the maximum load factor. + + Pointers and references to elements are never invalidated. + + The `template<class K>` overload only participates in overload resolution if `Hash::is_transparent` and `Pred::is_transparent` are valid member typedefs. The library assumes that `Hash` is callable with both `K` and `Key` and that `Pred` is transparent. This enables heterogeneous lookup which avoids the cost of instantiating an instance of the `Key` type.
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — 效果：;; 如果容器中尚不存在键与 `k` 等价的元素，则插入值 `std::pair<key_type const,="" mapped_type="">(k, mapped_type())`。 返回：;; 指向 `x.second` 的引用，其中 `x` 是容器中已存在的元素，或者是键与 `k` 等价的新插入元素。 抛出：;; 如果除调用 `hasher` 之外的操作抛出异常，则该函数无效。 备注：;; 可能使迭代器失效，但仅当插入导致负载因子大于或等于最大负载因子时才会发生。 此外，指向元素的指针和引用永远不会失效。 另外，仅当 `Hash::is_transparent` 和 `Pred::is_transparent` 是有效的成员 typedef 时，`template<class k="">` 重载才会参与重载决议。库假定 `Hash` 可同时以 `K` 和 `Key` 类型调用，且 `Pred` 是透明的。这支持了异构查找，从而避免了实例化 `Key` 类型的开销。</class></key_type> 466/9900 · 990 Needs editing
:1480 :1480
	English ---
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — --- 3/100 · 3 Needs editing
382 :1482
	English at
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — at 2/100 · 2 Needs editing
383 :1483
	English ```c++ mapped_type& at(const key_type& k); const mapped_type& at(const key_type& k) const; template<class K> mapped_type& at(const K& k); template<class K> const mapped_type& at(const K& k) const; ```
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — ```c++ mapped_type&amp; at(const key_type&amp; k); const mapped_type&amp; at(const key_type&amp; k) const; template<class k=""> mapped_type&amp; at(const K&amp; k); template<class k=""> const mapped_type&amp; at(const K&amp; k) const; ```</class></class> 254/2000 · 200 Needs editing
384 :1491
	English Returns:;; A reference to `x.second` where `x` is the (unique) element whose key is equivalent to `k`. Throws:;; An exception object of type `std::out_of_range` if no such element is present. Notes:;; The `template<class K>` overloads only participate in overload resolution if `Hash::is_transparent` and `Pred::is_transparent` are valid member typedefs. The library assumes that `Hash` is callable with both `K` and `Key` and that `Pred` is transparent. This enables heterogeneous lookup which avoids the cost of instantiating an instance of the `Key` type.
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — 返回：;; 指向 `x.second` 的引用，其中 `x` 是键与 `k` 等价的（唯一）元素。 抛出：;; 如果不存在这样的元素，则抛出 `std::out_of_range` 类型的异常对象。 备注：;; 仅当 `Hash::is_transparent` 和 `Pred::is_transparent` 是有效的成员 typedef 时，`template<class k="">` 重载才会参与重载决议。库假定 `Hash` 可同时以 `K` 和 `Key` 类型调用，且 `Pred` 是透明的。这支持了异构查找，从而避免了实例化 `Key` 类型的开销。</class> 293/5580 · 558 Needs editing
:1495 :1495
	English ---
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — --- 3/100 · 3 Needs editing
386 :1497
	English Bucket Interface
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — 桶接口 3/160 · 16 Needs editing
387 :1499
	English bucket_count
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — bucket_count 12/120 · 12 Needs editing
388 :1500
	English ```c++ size_type bucket_count() const noexcept; ```
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — ```c++ size_type bucket_count() const noexcept; ``` 51/510 · 51 Needs editing
389 :1505
	English Returns:;; The number of buckets.
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — 返回：;; 桶的数量。 11/330 · 33 Needs editing
:1507 :1507
	English ---
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — --- 3/100 · 3 Needs editing
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	English max_bucket_count
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — max_bucket_count 16/160 · 16 Needs editing
392 :1510
	English ```c++ size_type max_bucket_count() const noexcept; ```
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — ```c++ size_type max_bucket_count() const noexcept; ``` 55/550 · 55 Needs editing
393 :1515
	English Returns:;; An upper bound on the number of buckets.
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — 返回：;; 桶数量的上限。 13/510 · 51 Needs editing
:1517 :1517
	English ---
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — --- 3/100 · 3 Needs editing
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	English bucket_size
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — 桶大小 3/110 · 11 Needs editing
396 :1520
	English ```c++ size_type bucket_size(size_type n) const; ```
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — ```c++ size_type bucket_size(size_type n) const; ``` 52/520 · 52 Needs editing
397 :1525
	English Requires:;; `n < bucket_count()` Returns:;; The number of elements in bucket `n`.
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — 要求：;; `n &lt; bucket_count()`返回：;; 桶 `n` 中的元素个数。 48/810 · 81 Needs editing
:1528 :1528
	English ---
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — --- 3/100 · 3 Needs editing
399 :1530
	English bucket
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — 桶 1/100 · 6 Needs editing