2. Boost Unordered Translation (zh_Hans)
3. Doc / Modules / Root / Pages / Reference / Unordered Map (adoc)
4. Chinese (Simplified Han script)
5. Zen

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	English Requires:;; `nh` is empty or `nh.get_allocator()` is equal to the container's allocator. Returns:;; If `nh` was empty returns `end()`. + + If there was already an element in the container with an equivalent key returns an iterator pointing to that. + + Otherwise returns an iterator pointing to the newly inserted element. Throws:;; If an exception is thrown by an operation other than a call to hasher the function has no effect. Notes:;; The standard is fairly vague on the meaning of the hint. But the only practical way to use it, and the only way that Boost.Unordered supports is to point to an existing element with the same key. + + Can invalidate iterators, but only if the insert causes the load factor to be greater to or equal to the maximum load factor. + + Pointers and references to elements are never invalidated. + + This can be used to insert a node extracted from a compatible `unordered_multimap`.
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — 要求：`nh` 为空或 `nh.get_allocator()` 等于容器的分配器。 返回：如果 `nh` 为空，则返回 `end()`。 如果容器中已存在具有等价键的元素，则返回指向该元素的迭代器。 否则返回指向新插入元素的迭代器。 抛出：如果除调用 `hasher` 之外的操作抛出异常，则该函数无效果。 注意：标准关于 `hint` 的含义表述相当模糊。但唯一实际的使用方式，也是 Boost.Unordered 支持的唯一方式，是将其指向一个具有相同键的已存在元素。 可能使迭代器失效，但仅当插入导致负载因子大于或等于最大负载因子时才会发生。 指向元素的指针和引用永远不会失效。 此函数可用于插入从兼容的 `unordered_multimap` 中提取的节点。 351/9160 · 916 Needs editing
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	English Returns:;; The iterator following `position` before the erasure. Throws:;; Only throws an exception if it is thrown by `hasher` or `key_equal`. Notes:;; In older versions this could be inefficient because it had to search through several buckets to find the position of the returned iterator. The data structure has been changed so that this is no longer the case, and the alternative erase methods have been deprecated.
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — 返回：`position` 在被擦除之前的后一个迭代器。 抛出：仅当 `hasher` 或 `key_equal` 抛出异常时才会抛出。 注意：在旧版本中，此操作可能效率较低，因为它需要搜索多个桶以找到返回迭代器的位置。数据结构已经更改，不再是这种情况，并且备用的擦除方法已被弃用。 145/4200 · 420 Needs editing
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	English Returns:;; The number of elements erased. Throws:;; Only throws an exception if it is thrown by `hasher` or `key_equal`. Notes:;; The `template<class K>` overload only participates in overload resolution if `Hash::is_transparent` and `Pred::is_transparent` are valid member typedefs and neither `iterator` nor `const_iterator` are implicitly convertible from `K`. The library assumes that `Hash` is callable with both `K` and `Key` and that `Pred` is transparent. This enables heterogeneous lookup which avoids the cost of instantiating an instance of the `Key` type.
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — 返回：被擦除的元素数量。 抛出：仅当 `hasher` 或 `key_equal` 抛出异常时才会抛出。 注意：`template<class k="">` 重载仅在 `Hash::is_transparent` 和 `Pred::is_transparent` 是有效的成员 typedef，且 `iterator` 和 `const_iterator` 都不能从 `K` 隐式转换时参与重载决议。库假定 `Hash` 可同时使用 `K` 和 `Key` 调用，且 `Pred` 是透明的。这支持了异构查找，从而避免了实例化 `Key` 类型对象的开销。</class> 290/5670 · 567 Needs editing
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	English Returns:;; The iterator following the erased elements - i.e. `last`. Throws:;; Only throws an exception if it is thrown by `hasher` or `key_equal`. + + In this implementation, this overload doesn't call either function object's methods so it is no throw, but this might not be true in other implementations.
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — 返回：被擦除元素之后的迭代器——即 `last`。 抛出：仅当 `hasher` 或 `key_equal` 抛出异常时才会抛出。 在此实现中，此重载不会调用任何函数对象的方法，因此不会抛出异常，但这在其他实现中可能并不成立。 117/3070 · 307 Needs editing
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	English Returns:;; The number of erased elements. Notes:;; Equivalent to: + + ```c++ auto original_size = c.size(); for (auto i = c.begin(), last = c.end(); i != last; ) { if (pred(*i)) { i = c.erase(i); } else { ++i; } } return original_size - c.size(); ``` + Note that the references passed to `pred` are non-const.
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — 返回：;; 被移除的元素数量。备注：;; 等价于：```c++auto original_size = c.size();for (auto i = c.begin(), last = c.end(); i != last; ) { if (pred(*i)) { i = c.erase(i); } else { ++i; }}return original_size - c.size();```注意，传递给 `pred` 的引用是非常量的。 245/3090 · 309 Needs editing
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