2. Boost Unordered Translation (zh_Hans)
3. Doc / Modules / Root / Pages / Reference / Concurrent Node Map (adoc)
4. Chinese (Simplified Han script)
5. Zen

462 :1807
	English ```c++ void reset_stats() noexcept; ```
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — ```c++ void reset_stats() noexcept; ``` 39/390 · 39 Needs editing
463 :1812
	English Effects:;; Sets to zero the internal statistics kept by the table. Notes:;; Only available if xref:reference/stats.adoc#stats[statistics calculation] is xref:concurrent_node_map_boost_unordered_enable_stats[enabled].
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — 效果：;; 将容器维护的内部统计数据归零。 注意：;; 仅当 xref:reference/stats.adoc#stats[statistics calculation] 被 xref:concurrent_node_map_boost_unordered_enable_stats[enabled] 启用时可用。 158/2160 · 216 Needs editing
:1815 :1815
	English ---
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — --- 3/100 · 3 Needs editing
465 :1817
	English Deduction Guides
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — 推导指引 4/160 · 16 Needs editing
466 :1818
	English A deduction guide will not participate in overload resolution if any of the following are true:
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — 如果以下任何一条件为真，则推导指引将不参与重载决议： 26/950 · 95 Needs editing
467 :1820
	English - It has an `InputIterator` template parameter and a type that does not qualify as an input iterator is deduced for that parameter. - It has an `Allocator` template parameter and a type that does not qualify as an allocator is deduced for that parameter. - It has a `Hash` template parameter and an integral type or a type that qualifies as an allocator is deduced for that parameter. - It has a `Pred` template parameter and a type that qualifies as an allocator is deduced for that parameter.
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — - 该推导指引包含 `InputIterator` 模板参数，且为此参数推导出的类型不符合输入迭代器的要求。 - 该推导指引包含 `Allocator` 模板参数，且为该参数推导出的类型不符合分配器要求。 - 该推导指引包含 `Hash` 模板参数，且为该参数推导出的类型为整型或符合分配器要求。 - 该推导指引包含 `Pred` 模板参数，且为该参数推导出的类型符合分配器要求。 190/4940 · 494 Needs editing
468 :1825
	English A `size_­type` parameter type in a deduction guide refers to the `size_­type` member type of the table type deduced by the deduction guide. Its default value coincides with the default value of the constructor selected.
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — 推导指引中的 `size++_++type` 参数类型，指向由该推导指引所推导容器类型的 `size++_++type` 成员类型。其默认值与所选构造函数的默认值一致。 84/2190 · 219 Needs editing
469 :1829
	English __iter-value-type__
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — _iter-value-type_ 17/190 · 19 Needs editing
470 :1837
	English __iter-key-type__
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — __iter-key-type__ 17/170 · 17 Needs editing
471 :1845
	English __iter-mapped-type__
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — __iter-mapped-type__ 20/200 · 20 Needs editing
472 :1853
	English __iter-to-alloc-type__
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — __iter-to-alloc-type__ 22/220 · 22 Needs editing
473 :1862
	English Equality Comparisons
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — 相等性比较 5/200 · 20 Needs editing
474 :1864
	English operator
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — operator 8/100 · 8 Needs editing
475 :1865
	English ```c++ template<class Key, class T, class Hash, class Pred, class Alloc> bool operator==(const concurrent_node_map<Key, T, Hash, Pred, Alloc>& x, const concurrent_node_map<Key, T, Hash, Pred, Alloc>& y); ```
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — ```c++ template<class key,="" class="" t,="" hash,="" pred,="" alloc=""> bool operator==(const concurrent_node_map<key, t,="" hash,="" pred,="" alloc="">&amp; x, const concurrent_node_map<key, t,="" hash,="" pred,="" alloc="">&amp; y); ```</key,></key,></class> 261/2070 · 207 Needs editing
476 :1871
	English Returns `true` if `x.size() == y.size()` and for every element in `x`, there is an element in `y` with the same key, with an equal value (using `operator==` to compare the value types).
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — 若 `x.size() == y.size()`，且对于 `x` 中的每个元素，`y` 中均存在一个键相同、值相等（使用 `operator==` 比较值类型）的元素，则返回 `true`。 95/1850 · 185 Needs editing
:1874 :1874
	English Concurrency:;; Blocking on `x` and `y`. Notes:;; Behavior is undefined if the two tables don't have equivalent equality predicates.
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — 并发特性：;; 阻塞 `x` 与 `y`。 注意：;; 若两个表的相等性谓词不一致，行为未定义。 48/1310 · 131 Needs editing
:1877 :1877
	English ---
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — --- 3/100 · 3 Needs editing
479 :1879
	English operator!
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — operator! 9/100 · 9 Needs editing
480 :1880
	English ```c++ template<class Key, class T, class Hash, class Pred, class Alloc> bool operator!=(const concurrent_node_map<Key, T, Hash, Pred, Alloc>& x, const concurrent_node_map<Key, T, Hash, Pred, Alloc>& y); ```
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — ```c++ template<class key,="" class="" t,="" hash,="" pred,="" alloc=""> bool operator!=(const concurrent_node_map<key, t,="" hash,="" pred,="" alloc="">&amp; x, const concurrent_node_map<key, t,="" hash,="" pred,="" alloc="">&amp; y); ```</key,></key,></class> 261/2070 · 207 Needs editing
481 :1886
	English Returns `false` if `x.size() == y.size()` and for every element in `x`, there is an element in `y` with the same key, with an equal value (using `operator==` to compare the value types).
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — 若`x.size() == y.size()`，且`x`中每个元素在`y`中都存在键相同、值相等（使用`operator==`比较值类型）的对应元素，则返回`false`。 86/1860 · 186 Needs editing