2. Boost Unordered Translation (zh_Hans)
3. Doc / Modules / Root / Pages / Reference / Concurrent Flat Map (adoc)
4. Chinese (Simplified Han script)
5. Zen

370 :1540
	English ``` key_equal key_eq() const; ```
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — ``` key_equal key_eq() const; ``` 33/330 · 33 Needs editing
:1547 :1547
	English ---
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — --- 3/100 · 3 Needs editing
374 :1551
	English count
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — count 5/100 · 5 Needs editing
376 :1559
	English Returns:;; The number of elements with key equivalent to `k` (0 or 1). Notes:;; The `template<class K>` overload only participates in overload resolution if `Hash::is_transparent` and `Pred::is_transparent` are valid member typedefs. The library assumes that `Hash` is callable with both `K` and `Key` and that `Pred` is transparent. This enables heterogeneous lookup which avoids the cost of instantiating an instance of the `Key` type. + + In the presence of concurrent insertion operations, the value returned may not accurately reflect the true state of the table right after execution.
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — 返回值：匹配键 `k` 的元素数量（0 或 1）。 说明：仅当 `Hash::is_transparent` 和 `Pred::is_transparent` 为有效成员类型别名时，`template<class k="">` 重载版本才参与重载决议。库假定哈希函数可同时作用于 `K` 类型与键类型，且相等谓词是透明的，从而支持异构查找，避免实例化键类型带来的开销。 若存在并发插入操作，返回值可能无法精确反映容器执行后的真实状态。</class> 226/5900 · 590 Needs editing
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	English ---
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — --- 3/100 · 3 Needs editing
380 :1575
	English Returns:;; A boolean indicating whether or not there is an element with key equal to `k` in the table. Notes:;; The `template<class K>` overload only participates in overload resolution if `Hash::is_transparent` and `Pred::is_transparent` are valid member typedefs. The library assumes that `Hash` is callable with both `K` and `Key` and that `Pred` is transparent. This enables heterogeneous lookup which avoids the cost of instantiating an instance of the `Key` type. + + In the presence of concurrent insertion operations, the value returned may not accurately reflect the true state of the table right after execution.
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — 返回值：布尔值，表示容器中是否存在键等于 `k` 的元素。 说明：仅当 `Hash::is_transparent` 和 `Pred::is_transparent` 为有效成员类型别名时，`template<class k="">` 重载版本才参与重载决议。库假定哈希函数可同时作用于 `K` 类型与键类型，且相等谓词是透明的，从而支持异构查找，避免实例化键类型带来的开销。 若存在并发插入操作，返回值可能无法精确反映容器执行后的真实状态。</class> 230/6230 · 623 Needs editing
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	English ---
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — --- 3/100 · 3 Needs editing
383 :1584
	English bucket_count
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — bucket_count 12/120 · 12 Needs editing
384 :1585
	English ```c++ size_type bucket_count() const noexcept; ```
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — ```c++ size_type bucket_count() const noexcept; ``` 51/510 · 51 Needs editing
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	English ---
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — --- 3/100 · 3 Needs editing
389 :1597
	English ```c++ float load_factor() const noexcept; ```
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — ```c++ float load_factor() const noexcept; ``` 46/460 · 46 Needs editing
390 :1602
	English Returns:;; `static_cast<float>(size())/static_cast<float>(bucket_count())`, or `0` if `bucket_count() == 0`.
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — 返回值：`static_cast<float>(size())/static_cast<float>(bucket_count())`；若 `bucket_count() == 0`，则返回 `0`。</float></float> 116/1080 · 108 Needs editing
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	English ---
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — --- 3/100 · 3 Needs editing
393 :1608
	English ```c++ float max_load_factor() const noexcept; ```
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — ```c++ float max_load_factor() const noexcept; ``` 50/500 · 50 Needs editing
:1615 :1615
	English ---
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — --- 3/100 · 3 Needs editing
397 :1618
	English ```c++ void max_load_factor(float z); ```
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — ```c++ void max_load_factor(float z); ``` 41/410 · 41 Needs editing
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	English ---
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — --- 3/100 · 3 Needs editing
401 :1630
	English ```c++ size_type max_load() const noexcept; ```
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — ```c++ size_type max_load() const noexcept; ``` 47/470 · 47 Needs editing
402 :1635
	English Returns:;; The maximum number of elements the table can hold without rehashing, assuming that no further elements will be erased. Note:;; After construction, rehash or clearance, the table's maximum load is at least `max_load_factor() * bucket_count()`. This number may decrease on erasure under high-load conditions. + + In the presence of concurrent insertion operations, the value returned may not accurately reflect the true state of the table right after execution.
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — 返回值：容器在不进行重哈希的前提下可容纳的最大元素数量（假定不会再擦除任何元素）。 说明：容器在构造、重哈希或清空后，其最大负载量至少为 `max_load_factor() * bucket_count()`。在高负载条件下执行擦除操作时，该数值可能会降低。 若存在并发插入操作，返回值可能无法精确反映容器执行后的真实状态。 163/4700 · 470 Needs editing
:1642 :1642
	English ---
	Chinese (Simplified Han script) ↹ ↵ NBS … 「 」 『 』 ﹙-﹚ ‐ – — --- 3/100 · 3 Needs editing